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package com.abn.dsalgos.datastructure.stack;
import java.util.LinkedList;
import java.util.Queue;
import java.util.Stack;
/*
https://leetcode.com/problems/minimum-remove-to-make-valid-parentheses/
Given a string s of '(' , ')' and lowercase English characters.
Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions )
so that the resulting parentheses string is valid and return any valid string.
Formally, a parentheses string is valid if and only if:
It is the empty string, contains only lowercase characters, or
It can be written as AB (A concatenated with B), where A and B are valid strings, or
It can be written as (A), where A is a valid string.
Input: s = "lee(t(c)o)de)"
Output: "lee(t(c)o)de"
Explanation: "lee(t(co)de)" , "lee(t(c)ode)" would also be accepted.
Input: s = "))(("
Output: ""
Explanation: An empty string is also valid.
*/
public class MinimumMovesForValidParenthesis {
public String minimumMoves(String s) {
Stack<Integer> stack = new Stack<>();
Queue<Integer> queue = new LinkedList<>();
for(int i = 0; i < s.length(); i++) {
if(s.charAt(i) == '(') {
stack.push(i);
} else if(s.charAt(i) == ')') {
if(stack.isEmpty()) {
queue.add(i);
} else {
stack.pop();
}
}
}
while(!stack.isEmpty()) {
queue.add(stack.pop());
}
StringBuilder sb = new StringBuilder();
for(int i = 0; i < s.length(); i++) {
if(!queue.contains(i)) {
sb.append(s.charAt(i));
}
}
return sb.toString();
}
public static void main(String[] args) {
MinimumMovesForValidParenthesis minimumMovesForValidParenthesis = new MinimumMovesForValidParenthesis();
System.out.println(minimumMovesForValidParenthesis.minimumMoves("Lee(t(code))rs)"));
System.out.println(minimumMovesForValidParenthesis.minimumMoves("))(("));
}
}