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/*
还是一个int array,一开始递增然后递减.求最大最小.
最小就是两头数字比较取最小
source : http://www.mitbbs.com/article_t/JobHunting/32705311.html
G tel
*/
/*
最大值,我一开始说如果我工作中碰到了,我第一个想法用Arrays.sort,
对方说好,什么效率?我说NlogN or worst can be N^2.
然后对方说有没有更加快的,我开始想,然后他说logN可以做,
我说那就是binary search了,写下了binary serach的基本结构就是low high,
mid = (low+high)/2,
然后我自言自语说怎么比较呢?怎么比较才知道应该在mid左边还是右边继续搜寻?
愣了一下,然后对方说可以和邻居比较阿,我说对,就开始写.
写出基本架构,然后对对方说还有边界条件要查的,比如index不能小于0,
不能大于数组长度,我说我等等来写.对方说不用写了,我说哦.
*/
/*这个确实是据的节奏,第二题不该提sort的,直接二分查找。*/
/*
第二题提sort可能是个失分点,因为即使没有其他条件,一个array里面找最大和最小
也是O(n).
你自言自语“怎么比较才知道应该在mid左边还是右边继续搜寻”,可能给面试官的
映像是你还没有整理好思路就开始写代码了。
另外没写边界条件也是一个失分点。个人觉得变种binary search处理边界条件还是很
重要的。
*/
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