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24 changes: 24 additions & 0 deletions leetcode3/남효정/403. Frog Jump.py
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# 풀이 실패
class Solution:
def canCross(self, stones: List[int]) -> bool:
# 첫 점프는 무조건 1칸이라 1번 돌 없으면 바로 실패임
if stones[1] != 1:
return False

# 각 돌 위치별 도달했던 점프 거리(k) 집합 초기화
jumps = {stone: set() for stone in stones}
jumps[0].add(0)

for stone in stones:
for k in jumps[stone]:
# 이동 가능한 다음 점프 거리 반복문
for step in (k - 1, k, k + 1):
next_pos = stone + step
if step > 0 and next_pos in jumps:
jumps[next_pos].add(step)

# 마지막 돌에 도달 기록 있으면 성공임
return len(jumps[stones[-1]]) > 0